If the times/division control of an oscilloscope is set to 50 microseconds, what is the corresponding frequency of the displayed waveform?

If the times/division control of an oscilloscope is set to 50 microseconds, what is the corresponding frequency of the displayed waveform?

• A. 2 KHz
• B. 5 KHz
• C. 10 KHz
• D. 20 KHz

Answer: (D)

To determine the frequency of a waveform displayed on an oscilloscope, you can use the relationship between the time period and frequency. The time setting, in this case, is 50 microseconds per division, which represents the time it takes for one cycle of the waveform to be displayed across the grid of the oscilloscope. First, convert the time from microseconds to seconds: 50 microseconds is equal to 50 x 10^-6 seconds, or 0.000050 seconds. The frequency (f) can be calculated using the formula: \[ f = \frac{1}{T} \] Where \( T \) is the time period. By inserting the time period into the equation: \[ f = \frac{1}{0.000050 \text{ seconds}} \] This calculation will give you a frequency of: \[ f = 20000 \text{ Hz} \text{ or } 20 \text{ KHz} \] This confirms that the corresponding frequency of the displayed waveform is 20 KHz, making it the correct answer. Understanding this relationship between frequency and time period is fundamental in analyzing waveforms using oscilloscopes, as it helps in interpreting

To determine the frequency of a waveform displayed on an oscilloscope, you can use the relationship between the time period and frequency. The time setting, in this case, is 50 microseconds per division, which represents the time it takes for one cycle of the waveform to be displayed across the grid of the oscilloscope.

First, convert the time from microseconds to seconds: 50 microseconds is equal to 50 x 10^-6 seconds, or 0.000050 seconds. The frequency (f) can be calculated using the formula:

[

f = \frac{1}{T}

]

Where ( T ) is the time period. By inserting the time period into the equation:

[

f = \frac{1}{0.000050 \text{ seconds}}

]

This calculation will give you a frequency of:

[

f = 20000 \text{ Hz} \text{ or } 20 \text{ KHz}

]

This confirms that the corresponding frequency of the displayed waveform is 20 KHz, making it the correct answer. Understanding this relationship between frequency and time period is fundamental in analyzing waveforms using oscilloscopes, as it helps in interpreting